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Form the differential equation of all the lines which are normal to the line 3x + 2y + 7 = 0. - Mathematics and Statistics

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प्रश्न

Form the differential equation of all the lines which are normal to the line 3x + 2y + 7 = 0.

योग
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उत्तर

Slope of the line 3x - 2y + 7 = 0 is `(- 3)/-2 = 3/2`

∴ slope of normal to this line is `- 2/3`

Then the equation of the normal is

y = `- 2/3 "x" + "k"`, where k is an arbitrary constant.

Differentiating w.r.t. x, we get

`"dy"/"dx" = - 2/3 xx 1 + 0`

∴ `3"dy"/"dx" + 2 = 0`

This is the required D.E.

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Notes

The answer in the textbook is incorrect.

  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Differential Equations - Miscellaneous exercise 2 [पृष्ठ २१७]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 6 Differential Equations
Miscellaneous exercise 2 | Q 4.4 | पृष्ठ २१७

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