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Obtain the differential equation by eliminating the arbitrary constants from the following equation: x3 + y3 = 4ax - Mathematics and Statistics

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प्रश्न

Obtain the differential equation by eliminating the arbitrary constants from the following equation:

x3 + y3 = 4ax

योग
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उत्तर

x3 + y3 = 4ax     .....(1)

Differentiating both sides w.r.t. x, we get

`3"x"^2 + 3"y"^2 "dy"/"dx" = 4"a" xx 1`

∴ `3"x"^2 + 3"y"^2 "dy"/"dx" = 4"a"`

Substituting the value of 4a in (1), we get

`"x"^3 + "y"^3 = (3"x"^2 + 3"y"^2 "dy"/"dx")"x"`

∴ `"x"^3 + "y"^3 = 3"x"^3 + 3"xy"^2  "dy"/"dx"`

∴ `2"x"^3 + 3"xy"^2 "dy"/"dx" - "y"^3 = 0`

This is the required D.E.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Differential Equations - Exercise 6.2 [पृष्ठ १९६]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 6 Differential Equations
Exercise 6.2 | Q 1.01 | पृष्ठ १९६

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