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Choose the correct option from the given alternatives: The solution of dydxyxyxdydx=y+x2-y2x is

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प्रश्न

Choose the correct option from the given alternatives:

The solution of `"dy"/"dx" = ("y" + sqrt("x"^2 - "y"^2))/"x"` is

विकल्प

  • `sin^-1 ("y"/"x") = 2 log |"x"| + "c"`

  • `sin^-1 ("y"/"x") =  log |"x"| + "c"`

  • `sin ("y"/"x") = log |"x"| + "c"`

  • `sin ("y"/"x") = 2 log |"x"| + "c"`

MCQ
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उत्तर

`sin^-1 ("y"/"x") =  log |"x"| + "c"`

Hint:

`"dy"/"dx" = ("y" + sqrt("x"^2 - "y"^2))/"x"`

Put y = vx      ∴ `"dy"/"dx" = "v + x" "dv"/"dx"`

∴ `"v + x" "dv"/"dx" = ("vx" + sqrt("x"^2 - "v"^2"x"^2))/"x" = "v" + sqrt(1 - "v"^2)`

∴ `"x" "dv"/"dx" = sqrt(1 - "v"^2)`

∴ `int 1/sqrt(1 - "v"^2) "dv" = int 1/"x" "dx"`

∴ sin-1 v = log |x| + c

∴ sin-1 v `("y"/"x") = log |x| + "c"`.

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अध्याय 6: Differential Equations - Miscellaneous exercise 1 [पृष्ठ २१५]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 6 Differential Equations
Miscellaneous exercise 1 | Q 1.08 | पृष्ठ २१५

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