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Find the Term Independent of X in the Expansion of the Expression: (Vii) ( 1 2 X 1 / 3 + X − 1 / 5 ) 8

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प्रश्न

Find the term independent of x in the expansion of the expression: 

(vii)  \[\left( \frac{1}{2} x^{1/3} + x^{- 1/5} \right)^8\]

 

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उत्तर

(vii)  Suppose the (+ 1)th term in the given expression is independent of x.
Now, 

\[\left( \frac{1}{2} x^{1/3} + x^{- 1/5} \right)^8 \]
\[ T_{r + 1} = ^{8}{}{C}_r \left( \frac{1}{2} x^{1/3} \right)^{8 - r} ( x^{- 1/5} )^r \]
\[ =^{8}{}{C}_r . \frac{1}{2^{8 - r}} x^\frac{8 - r}{3} - \frac{r}{5} \]
\[\text{ For this term to be independent of x, we must have } \]
\[\frac{8 - r}{3} - \frac{r}{5} = 0\]
\[ \Rightarrow 40 - 5r - 3r = 0\]
\[ \Rightarrow 8r = 40\]
\[ \Rightarrow r = 5\]
\[\text{ Hence, the required term is the 6th term } . \]
\[\text{ Now, we have: } \]
\[ ^{8}{}{C}_5 \times \frac{1}{2^{8 - 5}}\]
\[ = \frac{8 \times 7 \times 6}{3 \times 2 \times 8} = 7\]

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अध्याय 18: Binomial Theorem - Exercise 18.2

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 18 Binomial Theorem
Exercise 18.2 | Q 16.07

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