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The Middle Term in the Expansion of ( 2 X 2 3 + 3 2 X 2 ) 10 is (A) 251 (B) 252 (C) 250 (D) None of These

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प्रश्न

The middle term in the expansion of \[\left( \frac{2 x^2}{3} + \frac{3}{2 x^2} \right)^{10}\] is 

 

विकल्प

  •  251

  • 252

  •  250

  •  none of these

     
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उत्तर

252 

\[\text{ Here, n, i . e . , 10, is an even number }  . \]

\[ \therefore \text{ Middle term } = \left( \frac{10}{2} + 1 \right)\text{ th term = 6th term} \]

\[\text{ Thus, we have: } \]

\[ T_6 = T_{5 + 1} \]

\[ = ^{10}{}{C}_5 \left( \frac{2 x^2}{3} \right)^{10 - 5} \left( \frac{3}{2 x^2} \right)^5 \]

\[ = \frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2} \times \frac{2^5}{3^5} \times \frac{3^5}{2^5}\]

\[ = 252\]

 

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अध्याय 18: Binomial Theorem - Exercise 18.4 [पृष्ठ ४७]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 18 Binomial Theorem
Exercise 18.4 | Q 10 | पृष्ठ ४७

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