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Middle term in the expansion of (a3 + ba)28 is ______. - Mathematics

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प्रश्न

Middle term in the expansion of (a3 + ba)28 is ______.

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उत्तर

Middle term in the expansion of (a3 + ba)28 is `""^28"C"_14  a^56 b^14`.

Explanation:

Number of term in the expansion (a3 + ba)28

= 28 + 1

= 29 (odd)

∴ Middle term = `(29 + 1)/2` = 15th term

∴ T15 = T14+1

= `""^28"C"_14  (a^3)^(28 - 14) *  (ba)^14`

= `""^28"C"_14  (a)^42 * b^14 * a^14`

= `""^28"C"_14  a^56b^14`.

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अध्याय 8: Binomial Theorem - Exercise [पृष्ठ १४६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 8 Binomial Theorem
Exercise | Q 30 | पृष्ठ १४६

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