मराठी

Find the Term Independent of X in the Expansion of the Expression: (Vii) ( 1 2 X 1 / 3 + X − 1 / 5 ) 8

Advertisements
Advertisements

प्रश्न

Find the term independent of x in the expansion of the expression: 

(vii)  \[\left( \frac{1}{2} x^{1/3} + x^{- 1/5} \right)^8\]

 

Advertisements

उत्तर

(vii)  Suppose the (+ 1)th term in the given expression is independent of x.
Now, 

\[\left( \frac{1}{2} x^{1/3} + x^{- 1/5} \right)^8 \]
\[ T_{r + 1} = ^{8}{}{C}_r \left( \frac{1}{2} x^{1/3} \right)^{8 - r} ( x^{- 1/5} )^r \]
\[ =^{8}{}{C}_r . \frac{1}{2^{8 - r}} x^\frac{8 - r}{3} - \frac{r}{5} \]
\[\text{ For this term to be independent of x, we must have } \]
\[\frac{8 - r}{3} - \frac{r}{5} = 0\]
\[ \Rightarrow 40 - 5r - 3r = 0\]
\[ \Rightarrow 8r = 40\]
\[ \Rightarrow r = 5\]
\[\text{ Hence, the required term is the 6th term } . \]
\[\text{ Now, we have: } \]
\[ ^{8}{}{C}_5 \times \frac{1}{2^{8 - 5}}\]
\[ = \frac{8 \times 7 \times 6}{3 \times 2 \times 8} = 7\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 18: Binomial Theorem - Exercise 18.2

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 18 Binomial Theorem
Exercise 18.2 | Q 16.07

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the coefficient of x5 in (x + 3)8


Find the coefficient of a5b7 in (a – 2b)12


Prove that the coefficient of xn in the expansion of (1 + x)2n is twice the coefficient of xn in the expansion of (1 + x)2n–1 .


Find n, if the ratio of the fifth term from the beginning to the fifth term from the end in the expansion of `(root4 2 + 1/ root4 3)^n " is " sqrt6 : 1`


Find the middle terms in the expansion of:

(ii) \[\left( 2 x^2 - \frac{1}{x} \right)^7\]

 


Find the middle terms in the expansion of:

(iv)  \[\left( x^4 - \frac{1}{x^3} \right)^{11}\]

 


Find the middle terms(s) in the expansion of:

(ii)  \[\left( 1 - 2x + x^2 \right)^n\]


Find the middle terms(s) in the expansion of:

(iii)  \[\left( 1 + 3x + 3 x^2 + x^3 \right)^{2n}\]

 


Find the middle terms(s) in the expansion of:

(ix)  \[\left( \frac{p}{x} + \frac{x}{p} \right)^9\]

 


Find the term independent of x in the expansion of the expression:

(ii)  \[\left( 2x + \frac{1}{3 x^2} \right)^9\]

 


Find the term independent of x in the expansion of the expression: 

(iii)  \[\left( 2 x^2 - \frac{3}{x^3} \right)^{25}\]

 


Find the term independent of x in the expansion of the expression: 

(v)  \[\left( \frac{\sqrt{x}}{3} + \frac{3}{2 x^2} \right)^{10}\]

 


If the coefficients of \[\left( 2r + 4 \right)\text{ th and } \left( r - 2 \right)\] th terms in the expansion of  \[\left( 1 + x \right)^{18}\]  are equal, find r.

 
 
 

The coefficients of 5th, 6th and 7th terms in the expansion of (1 + x)n are in A.P., find n.

 

If in the expansion of (1 + x)n, the coefficients of pth and qth terms are equal, prove that p + q = n + 2, where  \[p \neq q\]

 


If in the expansion of (1 + x)n, the coefficients of three consecutive terms are 56, 70 and 56, then find n and the position of the terms of these coefficients.


If 3rd, 4th 5th and 6th terms in the expansion of (x + a)n be respectively a, b, c and d, prove that `(b^2 - ac)/(c^2 - bd) = (5a)/(3c)`.


If the coefficients of three consecutive terms in the expansion of (1 + x)n be 76, 95 and 76, find n.


If the 6th, 7th and 8th terms in the expansion of (x + a)n are respectively 112, 7 and 1/4, find xan.


Write the middle term in the expansion of  \[\left( x + \frac{1}{x} \right)^{10}\]

 

If an the expansion of \[\left( 1 + x \right)^{15}\]   , the coefficients of \[\left( 2r + 3 \right)^{th}\text{  and  } \left( r - 1 \right)^{th}\]  terms are equal, then the value of r is

 

In the expansion of \[\left( \frac{1}{2} x^{1/3} + x^{- 1/5} \right)^8\] , the term independent of x is

 

If the sum of odd numbered terms and the sum of even numbered terms in the expansion of  \[\left( x + a \right)^n\]  are A and B respectively, then the value of \[\left( x^2 - a^2 \right)^n\] is 

 

The number of terms with integral coefficients in the expansion of \[\left( {17}^{1/3} + {35}^{1/2} x \right)^{600}\] is

 

Find the term independent of x in the expansion of `(3x - 2/x^2)^15`


Show that the middle term in the expansion of `(x - 1/x)^(2x)` is `(1 xx 3 xx 5 xx ... (2n - 1))/(n!) xx (-2)^n`


If the middle term of `(1/x + x sin x)^10` is equal to `7 7/8`, then value of x is ______.


The last two digits of the numbers 3400 are 01.


If the expansion of `(x - 1/x^2)^(2n)` contains a term independent of x, then n is a multiple of 2.


If n is the number of irrational terms in the expansion of `(3^(1/4) + 5^(1/8))^60`, then (n – 1) is divisible by ______.


The coefficient of x256 in the expansion of (1 – x)101(x2 + x + 1)100 is ______.


The number of rational terms in the binomial expansion of `(4^(1/4) + 5^(1/6))^120` is ______.


The middle term in the expansion of (1 – 3x + 3x2 – x3)6 is ______.


Let for the 9th term in the binomial expansion of (3 + 6x)n, in the increasing powers of 6x, to be the greatest for x = `3/2`, the least value of n is n0. If k is the ratio of the coefficient of x6 to the coefficient of x3, then k + n0 is equal to ______.


If the coefficient of x10 in the binomial expansion of `(sqrt(x)/5^(1/4) + sqrt(5)/x^(1/3))^60` is 5kl, where l, k ∈ N and l is coprime to 5, then k is equal to ______.


Let the coefficients of the middle terms in the expansion of `(1/sqrt(6) + βx)^4, (1 - 3βx)^2` and `(1 - β/2x)^6, β > 0`, common difference of this A.P., then `50 - (2d)/β^2` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×