मराठी

If the middle term of (1x+xsinx)10 is equal to 778, then value of x is ______. - Mathematics

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प्रश्न

If the middle term of `(1/x + x sin x)^10` is equal to `7 7/8`, then value of x is ______.

पर्याय

  • `2npi + pi/6`

  • `npi + pi/6`

  • `npi + (-1)^n  pi/6`

  • `npi + (-1)^n  pi/3`

MCQ
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उत्तर

If the middle term of `(1/x + x sin x)^10` is equal to `7 7/8`, then value of x is `npi + (-1)^n  pi/6`.

Explanation:

Given expression is `(1/x + x sin x)^10`

Number of terms = 10 + 1 = 11 odd

∴ Middle term = `(11 + 1)/2` th term = 6th term

T6 = T5+1

= `""^10"C"_5 (1/x)^(10 - 5)  (x sin x)^5`

∴ `""^10"C"_5 (1/x)^5 * x^5 * sin^5x = 7 7/8`

⇒ `""^10"C"_5 * sin^5x = 63/8`

⇒ `(10*9*8*7*6)/(5*4*3*2*1) * sin^5x = 63/8`

⇒ `252 * sin^5x = 63/8`

⇒ `sin^5x = 63/(8 xx 252)`

⇒ `sin^5x = 1/32`

⇒ `sin^5x = (1/2)^5`

⇒ sin x = `1/2`

⇒ sin x = `sin  pi/6`

∴ x = `"n"pi + (-1)^"n" * pi/6`

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पाठ 8: Binomial Theorem - Exercise [पृष्ठ १४५]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 8 Binomial Theorem
Exercise | Q 24 | पृष्ठ १४५

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