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Find the Term Independent of X in the Expansion of the Expression: (Ix) ( 3 √ X + 1 2 3 √ X ) 18 , X > 0 - Mathematics

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प्रश्न

Find the term independent of x in the expansion of the expression: 

(ix) \[\left( \sqrt[3]{x} + \frac{1}{2 \sqrt[3]{x}} \right)^{18} , x > 0\]

 

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उत्तर

(ix) Suppose the (r + 1)th term in the given expression is independent of x.
Now, 

\[\left( \sqrt[3]{x} + \frac{1}{2\sqrt[3]{x}} \right)^{18} \]
\[ T_{r + 1} =^{18}{}{C}_r ( x^{1/3} )^{18 - r} \left( \frac{1}{2 x^{1/3}} \right)^r \]
\[ =^{18}{}{C}_r \times \frac{1}{2^r} x^\frac{18 - r}{3} - \frac{r}{3} \]
\[\text{ For this term to be independent of r, we must have } \]
\[\frac{18 - r}{3} - \frac{r}{3} = 0\]
\[ \Rightarrow 18 - 2r = 0\]
\[ \Rightarrow r = 9\]
\[\text{ The term is } \]
\[^{18}{}{C}_9 \times \frac{1}{2^9}\]

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अध्याय 18: Binomial Theorem - Exercise 18.2 [पृष्ठ ३९]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 18 Binomial Theorem
Exercise 18.2 | Q 16.09 | पृष्ठ ३९

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