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The position of the term independent of x in the expansion of (x3+32x2)10 is ______. - Mathematics

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प्रश्न

The position of the term independent of x in the expansion of `(sqrt(x/3) + 3/(2x^2))^10` is ______.

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उत्तर

The position of the term independent of x in the expansion of `(sqrt(x/3) + 3/(2x^2))^10` is 3rd term.

Explanation:

The given expansion is `(sqrt(x/3) + 3/(2x^2))^10`

Tr+1 = `""^10"C"_r (sqrt(x/3))^(10 - r) (3/(2x^2))^r`

= `""^10"C"_r (x/3)^((10 - r)/2) (3/2)^r * 1/x^(2r)`

= `""^10"C"_r (1/3)^((10 - r)/2) * x^((10 - r)/2) (3/2)^r * 1/x^(2r)`

= `""^10"C"_r (1/3)^((10 - r)/2) * x^((10 - r)/2 - 2r) * (3/2)^r`

= `""^10"C"_r (1/3)^((10 - r)/2) * x^((10 - r - 4r)/2) (3/2)^r`

For independent of x, we get

`(10 - r - 4r)/2` = 0

10 – 5r = 0

r = 2

So, the position of the term independent of x is 3rd term.

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अध्याय 8: Binomial Theorem - Exercise [पृष्ठ १४६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 8 Binomial Theorem
Exercise | Q 32 | पृष्ठ १४६

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