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Consider the reaction: 6COX2(g)+6HX2O(l)⟶CX6 HX12OX6(aq)+6OX2(g) Why it is more appropriate to write these reaction as: 6COX2(g)+12HX2O(l)⟶CX6 HX12OX6(aq)+6HX2O(l)+6OX2(g)

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प्रश्न

Consider the reaction:

\[\ce{6 CO2(g) + 6H2O(l) → C6 H12O6(aq) + 6O2(g)}\]

Why it is more appropriate to write these reaction as:

\[\ce{6CO2(g) + 12H2O(l) → C6 H12O6(aq) + 6H2O(l) + 6O2(g)}\]

Also, suggest a technique to investigate the path of the redox reactions.

संक्षेप में उत्तर
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उत्तर

The process of photosynthesis involves two steps.

Step 1:

H2O decomposes to give H2 and O2.

Step 2:

The H2 produced in step 1 reduces CO2, thereby producing glucose (C6H12O6) and H2O.

\[\ce{6CO_{2(g)} + 12H_{2(g)}  -> C_6H_12O_{6(s)} + 6H_2O_{(l)}}\]

Now, the net reaction of the process is given as:

\[\ce{2H_2O_{(l)} -> 2H_{2(g)} + O_{2(g)} ] × 6}\]
\[\ce{6CO_{2(g)} + 12H_{2(g)} -> C_6H_12O_{6(g)} + 6H_2O_{(l)}}\]

\[\ce{6CO_{2(g)} + 12H_2O_{(l)} -> C_6H_12O_{6(g)} +  6H_2O_{(l)} + 6O_{2(g)}}\]

It is more appropriate to write the reaction as given above because water molecules are also produced in the process of photosynthesis.

The path of this reaction can be investigated by using radioactive H2O18 in place of H2O.

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अध्याय 7: Redox Reactions - EXERCISES [पृष्ठ २८०]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 11
अध्याय 7 Redox Reactions
EXERCISES | Q 8.9 (a) | पृष्ठ २८०

संबंधित प्रश्न

The compound AgF2 is an unstable compound. However, if formed, the compound acts as a very strong oxidizing agent. Why?


Balance the following redox reactions by ion-electron method:

  1. \[\ce{MnO-_4 (aq) + I– (aq) → MnO2 (s) + I2(s) (in basic medium)}\]
  2. \[\ce{MnO-_4 (aq) + SO2 (g) → Mn^{2+} (aq) + HSO-_4  (aq) (in acidic solution)}\]
  3. \[\ce{H2O2 (aq) + Fe^{2+} (aq) → Fe^{3+} (aq) + H2O (l) (in acidic solution)}\]
  4. \[\ce{Cr_2O^{2-}_7 + SO2(g) → Cr^{3+} (aq) + SO^{2-}_4 (aq) (in acidic solution)}\]

Balance the following equation in basic medium by ion-electron method and oxidation number methods and identify the oxidising agent and the reducing agent.

\[\ce{P4(s) + OH–(aq) —> PH3(g) + HPO^–_2(aq)}\]


Balance the following equation in the basic medium by ion-electron method and oxidation number methods and identify the oxidising agent and the reducing agent.

\[\ce{N2H4(l) + ClO^-_3 (aq) → NO(g) + Cl–(g)}\]


Balance the following reaction by oxidation number method.

\[\ce{H2SO4_{(aq)} + C_{(s)} -> CO2_{(g)}  + SO2_{(g)} + H2O_{(l)}(acidic)}\]


Balance the following reaction by oxidation number method.

\[\ce{Bi(OH)_{3(s)} + Sn(OH)^-_{3(aq)}->Bi_{(s)}  + Sn(OH)^2-_{6(aq)}(basic)}\]


Balance the following redox equation by half-reaction method.

\[\ce{H2C2O_{4(aq)} + MnO^-_{4(aq)}->CO2_{(g)} + Mn^2+_{( aq)}(acidic)}\]


Identify coefficients 'x' and 'y' for the following reaction.

\[\ce{{x}H2O2_{(aq)} + ClO^-_{4(aq)} -> 2O2_{(g)} + ClO^-_{2(aq)} + {y}H2O_{(l)}}\]


Write balanced chemical equation for the following reactions:

Reaction of liquid hydrazine \[\ce{(N2H4)}\] with chlorate ion \[\ce{(ClO^{-}3)}\] in basic medium produces nitric oxide gas and chloride ion in gaseous state.


Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them.

\[\ce{Fe2O3 (s) + 3CO (g) ->[Δ] 2Fe (s) + 3CO2 (g)}\]


Balance the following ionic equations.

\[\ce{Cr2O^{2-}7 + H^{+} + I- -> Cr^{3+} + I2 + H2O}\]


Balance the following ionic equations.

\[\ce{Cr2O^{2-}7 + Fe^{2+} + H+ -> Cr^{3+} + Fe^{3+} + H2O}\]


Balance the following ionic equations.

\[\ce{MnO^{-}4 + SO^{2-}3 + H^{+} -> Mn^{2+} + SO^{2-}4 + H2O}\]


Balance the following ionic equations.

\[\ce{MnO^{-}4 + H^{+} + Br^{-} -> Mn^{2+} + Br2 + H2O}\]


In acidic medium, reaction, \[\ce{MNO^-_4 → Mn^2+}\] an example of ____________.   


The weight of CO is required to form Re2(CO)10 will be ______ g, from 2.50 g of Re2O7 according to given reaction

\[\ce{Re2O7 + CO -> Re2(CO)10 + CO2}\]

Atomic weight of Re = 186.2; C = 12 and O = 16.


In the reaction of oxalate with permanganate in an acidic medium, the number of electrons involved in producing one molecule of CO2 is ______.


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