हिंदी

A rod of magnetic material of cross-section 0.25 cm2 is placed in a magnetizing field of intensity 4000 A/m. The magnetic flux passing through the rod is 25 x 10-6 Wb. Find out

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प्रश्न

A rod of magnetic material of cross-section 0.25 cm2 is placed in a magnetizing field of intensity 4000 A/m-1. The magnetic flux passing through the rod is 25 × 10-6 Wb. Find out

(a) relative permeability

(b) magnetic susceptibility and 

(c) magnetisation of the rod.

योग
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उत्तर

Given: A = 0.25 cm2 = 25 × 10-6 m2

H = 4000 A m-1, Φ = 25 × 10-6 Wb

Magnetic induction is

B = `phi/"A"`

`= (25 xx 10^-6)/(25 xx 10^-6)`

= 1 Wb/m2

(a) B = μ0μrH

∴ The relative permeability of the material,

`mu_"r" = "B"/(mu_0"H")`

`= 1/(4 xx 3.142 xx 10^-7 xx 4000)`

`= 10000/50.272`

= 198.91 = 199

(b) `mu_"r" = 1 + chi_"m"`

∴ The magnetic susceptibility of the material,

`chi_"m" = mu_"r" - 1`

= 199 - 1

= 198

(c) `chi_"m" = "M"_"z"/"H"`

The magnetization of the rod,

`"M"_"z" = chi_"m""H" = 198 xx 4000 = 7.92 xx 10^5`A/m

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अध्याय 11: Magnetic Materials - Exercises [पृष्ठ २६४]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 11 Magnetic Materials
Exercises | Q 4. | पृष्ठ २६४

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