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![SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board chapter 7 - Mensuration SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board chapter 7 - Mensuration - Shaalaa.com](/images/geometry-mathematics-2-english-10-standard-ssc_6:5f2b1b2038084cf381bfa42c826a928c.jpg)
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Solutions for Chapter 7: Mensuration
Below listed, you can find solutions for Chapter 7 of Maharashtra State Board SCERT Maharashtra for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board.
SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board 7 Mensuration Q.1 (A)
MCQ
If the dimensions of a cuboid in cm are 16 × 14 × 20, then its total surface area is ______.
4480 cm2
1648 cm2
824 cm2
1740 cm2
The total surface area of hemisphere is 300 πcm2, then find its radius.
8 cm
12 cm
10 cm
9 cm
Find the perimeter of a sector of a circle if its measure is 90° and radius is 7 cm.
25 cm
44 cm
36 cm
56 cm
The radius of a cone is 7 cm and height is 24 cm. What is its curred surface area?
550 cm2
110 cm2
440 cm2
330 cm2
For a cuboid l2 + b2 + h2 = 484 cm2 then what is the length of its diagonal?
12 cm
22 cm
11 cm
24 cm
If the radius of the sector is 6 and length of its corresponding are is 14, then area of the sector is ______.
35
84
42
24
Find the ratio of the volumes of a cylinder and cone having equal radius and equal height.
1 : 3
3 : 1
2 : 1
1 : 2
The height of cone is 12 cm and radius is 5 cm then its slant height ______.
17 cm
60 cm
7 cm
13 cm
What is volume of the bath tub in litres if its volume in cm3 is 2058?
2058
20.58
2.058
205.8
A solid sphere of diameter 6 cm is melted and drawn into a wire of radius 4 mm. The length of wire is ______.
90° cm
90 cm
900 m
225 cm
SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board 7 Mensuration Q.1 (B)
Find the area of the segment of a circle of radius 7 cm whose corresponding sector has a central angle of 60° (π = 3.14).
Area of a sector of a circle of radius 15 cm is 30 cm2. Find the length of the arc of the sector.
Radius of sector of a circle is 5 cm and length of its arc is 2.8 cm. Find the area of the sector.
Find the surface area of sphere of radius 4.2 cm.
The radii of circular ends of frustum of a cone are 20 cm and 12 cm and its height is 6 cm. Find the Slant height of frustum.
SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board 7 Mensuration Q.2 (A)
If the heights of two cylinders are equal and their radii are in the ratio of 7 : 5 then the ratio of their volumes is......
Volume of cylinder = `square` .......(Formula)
= h2
`square/r_2 = 7/square`
`(πr^2h_1)/(πr^2h_2) = 49/25`
A road roller of length 3`l`m and radius `l/3` m can cover field in 100 revolutions moving once over. The area of the field in terms of `l` ......... m2
Curved surface area = 2πrh
h = `square` m
`square = l/3` m
∴ Curved surface area of cylinder = `square` × 2
∴ Area of field = 2πrl2 × 100 = `square`
Find the volume of greatest right circular cone, which can be cut from a cube of a side 4 cm.
Let, diameter of cone be edge of the square
∴ `l = square` cm
∴ h = `square` 4 cm
r = 2 cm
Volume of cone = `square` ...........(Formula)
V = `1/3 π square^3 xx 4`
V = `square` cm3
The measure of central angle of circle is 150° and the radius of circle is 21 cm. To find the length of the arc complete the following activity.
Length of arc = `l = θ/(360^circ) xx square`
= `(150^circ)/square xx square xx 22/7 xx 2`
= `square` cm
A right circular cone in such that the angle of at its vertex is 90º and its base radius is 49 cm. Then find the curved surface area of the cone?
Let slant height be x and ⊥ will bisect vertex angle.
∴ Δ ABC is right angle Δ
∴ x2 + x2 = (49 × 2)2
x2 = 4802
Curved surface area of cone = `square` ...(Formula)
= `22/7 xx 49 xx square`
= `22/7 xx square xx 49sqrt(2)`
= `square` cm2
SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board 7 Mensuration Q.2 (B)
Solve the following questions.
The diameter of a garden roller is 1.4 m and it is 2 m long. How much area will it is 2 m long. How much area will it cover in 5 revolutions. `(π = 22/7)`
Find the surface area of a sphere of radius 3.5 cm.
The volume of a cube is 1000 cm3. Find its total surface area.
A cone of height 24 cm has a plane base of surface area 154 cm2. Find its volume.
Find the surface area of hemisphere with radius 10 cm (π = 3.14).
In figure, point O is the center of the circle.
∠AOB = 30º, OA = 12 cm.
Find the area of segment AXB (π = 3.14)

SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board 7 Mensuration Q.3 (A)
The circumferences of circular faces of frustum are 132 cm and 88 cm and its height is 24 cm, to find the curved surface area of the frustum complete the following activity. `(π = 22/7)`
Circumference1 = 2πr1 = 132
`r_1 = 132/(2π) = square`
Circumference2 = 2 = 2πr2 = 88
`r_2 = 88/(2π) = square`
Slant height frustum = `(l) = sqrt(h^2 + (r_1 - r_2)^2`
= `sqrt(square^2 + square^2)`
= `square` cm
∴ Curved surface area of frustum = `π(r_1 + r_2)l = square cm^2`
The circumference of circular faces of a frustum.
The area of a minor sector of a circle is 3.85 cm2. The measure of its central angle is 36°. Find the radius of circle.
Area of minor sector = 3.85 cm2
Measure of its central angle (θ) = 150°
Let, its radius be r
Area of minor sector = `θ/(150^circ) xx square`
`3.85 = (36^circ)/(360^circ) xx 22/7 xx r^2`
`r^2 = (square xx square xx square)/square`
r2 = 12.25
r = `square`
A hollow hemisphere bowl of thickness 1 cm has an inner radius of 6 cm. Find the volume of metal required to make the bowl.
Inner Radius r = 6 cm
Thickness, t = 1 cm
∴ Outer Radius (R) = 6 + 1 = 7 cm
∴ Volume of steel required = `2/3 πr^3 - 2/3 πr^3`
= `2/3 xx 22/7 xx square^3 - 2/3 xx 22/7 xx square^3`
= `44/21 (square - 6^3)`
= `44/21 xx (square - square)`
= `44/21 xx square`
= `5588/21` cm2
In the figure given below, ABCD is a square of side 7 cm. BD is an arc of a circle of radius AB. What is the area of shaded region.
Area of shaded region = 2(Area of sector BAD − Area of ΔABD)
= `[(90^circ)/(360^circ) xx square xx 7^2 - square xx 7^2]`
= `2[1/4 xx 154 - square]`
= `2/2[77 - square]`
= `square` cm2
A square of side 28 cm is folded into a cylinder by joining its two sides. Find the base area of the cylinder thus formed.
Area of square = Total surface area of cylinder
(28)2 = 2πrh
= 2 × 22 × r × 28
`r = ((28)^2 xx 7)/(2 xx 22 xx square)`
`r = square/11`
Base area of cylindesr = πr2
= `22/7 xx 49/square xx square/11`
= `square/square` cm2
SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board 7 Mensuration Q.3 (B)
In a clock, the minute hand is of length 7 cm. Find the area covered by the minute hand in 5 minutes.
Three cubes each of side 15 cm joined end to end. Find the total surface area of the rusting cuboid.
The radii of the circular ends of a frustum of a cone are 14 cm and 8 cm. If the height of the frustum is 8 cm find:
- Slant height of frustum.
- Total surface area of frustum.
- Volume of frustum (π = 3.14)
A sector of a circle of radius 15 cm has the angle 120º. It is rolled up so that two bounding radii are joined together to form a cone. Find the volume of the cone. `(π = 22/7)`
A metallic sphere of radius 10.5 cm is melted and then recast into small cones, each of radius 3.5 cm and height is 3 cm. Find how many cones are obtained?
SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board 7 Mensuration Q.4
An oil funnel made of tin sheet consists of a cylindrical portion 10 cm long attached to a frustum of a cone. If the total height is 22 cm, diameter of the cylindrical portion is 8 cm and the diameter of the top of funnel is 18 cm. Find the area of tin required to make the funnel.

A toy is in the form of a cone mounted on a hemisphere. The diameter of the base of the cone and that of a hemisphere is 18 cm and the height of cone is 12 cm. Find the total surface area of toy. (π = 3.14)
A farmer connects a pipe of internal diameter 20 cm from the canal into a cylindrical tank in his field, which is 10 m in diameter and 2 m deep. If water flows through the rate of 3 km/h, in how much time will the tank be filled?

How many coins 1.75 cm in diameter and 2 mm thick must be melted to form a cuboid 11 cm × 10 cm × 7 cm?
SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board 7 Mensuration Q.5
Write True or False and justify your answer in the following.
A solid ball is exactly fitted inside the cubical box of side b, The volume of ball is `4/3 πb^3`.
Write True or False and justify your answer in the following.
The capacity of cylindrical vessel with a hemispherical portion raised upward at the bottom as shown in fig. is πr3(3h – 2r) where r is radius in c3m and h cm is height.

In the above figure, a sphere is placed in a cylinder. It touches the top, bottom and curved surface of the cylinder. If the radius of the base of the cylinder is ‘r’, write the answer to the following questions.
- What is the height of the cylinder in terms of ‘r’?
- What is the ratio of the curved surface area of the cylinder and the surface area of the sphere?
- What is the ratio of volumes of the cylinder and of the sphere?
A horse is tied to a peg at one corner of square shaped grass field of side 15 m by means of 5 m long rope, find
- The area of that part of the field in which the horse can graze.
- The increase in the grazing area if the rope were 10 m long instead of 5 m. (π = 3.14)
A donor agency ensures milk is supplied in containers, which are in the form of a frustum of cone to be distributed to flood victims in a camp. The height of each frustum is 30 cm and the radii of lower and upper circular ends are 20 cm and 40 cm respectively. If this milk is available at the rate of ₹ 35 per litre and 8800 litres of milk is needed daily for a camp.
- Find how many milk containers are needed daily for the camp.
- What daily cost will put on the donor agency?
Solutions for 7: Mensuration
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SCERT Maharashtra solutions for Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board chapter 7 - Mensuration
Shaalaa.com has the Maharashtra State Board Mathematics Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board Maharashtra State Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. SCERT Maharashtra solutions for Mathematics Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board Maharashtra State Board 7 (Mensuration) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board chapter 7 Mensuration are Conversion of Solid from One Shape to Another, Frustum of a Cone, Length of an Arc, Euler's Formula, Circumference of a Circle, Sector of a Circle, Area of a Sector, Segment of a Circle, Area of a Segment, Overview of Mensuration.
Using SCERT Maharashtra Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board solutions Mensuration exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in SCERT Maharashtra Solutions are essential questions that can be asked in the final exam. Maximum Maharashtra State Board Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board students prefer SCERT Maharashtra Textbook Solutions to score more in exams.
Get the free view of Chapter 7, Mensuration Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board additional questions for Mathematics Geometry (Mathematics 2) [English] Standard 10 Maharashtra State Board Maharashtra State Board, and you can use Shaalaa.com to keep it handy for your exam preparation.
