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Maharashtra State BoardSSC (English Medium) 10th Standard

The circumference of circular faces of a frustum.

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Question

The circumference of circular faces of a frustum.

Sum
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Solution

Given:

Circumferences of the two circular faces: C1 and C2.

Radius of corresponding faces: r1 and r2.

Step-wise calculation:

1. Use the circle circumference formula: C = 2πr.

2. Solve for each radius:

`r_1 = (C_1)/(2π)`

`r_2 = (C_2)/(2π)`

3. If you need the circumferences from radii, compute:

C1 = 2πr1

C2 = 2πr2

If C1 = 132 cm and C2 = 88 cm, then

`r_1 = 132/(2π)`

= 21 cm

`r_2 = 88/(2π)`

= 14 cm

Circumferences of the frustum’s circular faces are C1 = 2πr1 and C2 = 2πr2.

Given C1 and C2, compute radii by `r_1 = (C_1)/(2π)` and `r_2 = (C_2)/(2π)`

E.g., C1 = 132 cm → r1 = 21 cm,

C2 = 88 cm → r2 = 14 cm.

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Chapter 7: Mensuration - Q.3 (A)
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