Question

The area of a minor sector of a circle is 3.85 cm². The measure of its central angle is 36°. Find the radius of circle.

Area of minor sector = 3.85 cm²

Measure of its central angle (θ) = 36°

Let, its radius be r.

Area of minor sector = `θ/(360^circ) xx square`

`3.85 = (36^circ)/(360^circ) xx 22/7 xx r^2`

`r^2 = (square xx square xx square)/square`

r² = 12.25

r = `square`

Answer 1

Area of minor sector = 3.85 cm²

Measure of its central angle (θ) = 36°

Let, its radius be r.

Area of minor sector \[= \frac{θ}{360°} \times \boxed{πr^2}\]

`3.85 = (36^circ)/(360^circ) xx 22/7 xx r^2`

\[r^2 = \frac{\boxed{3.85} \times \boxed{10} \times \boxed{7}}{\boxed{22}}\]

r² = 12.25

r = = \[\boxed{3.5 \text{ cm}}\]