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Maharashtra State BoardSSC (English Medium) 10th Standard

In the figure given below, ABCD is a square of side 7 cm. BD is an arc of a circle of radius AB. What is the area of shaded region. Area of shaded region = 2(Area of sector BAD − Area of ΔABD)

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Question

In the figure given below, ABCD is a square of side 7 cm. BD is an arc of a circle of radius AB. What is the area of shaded region.

Area of shaded region = 2(Area of sector BAD − Area of ΔABD)

= `[(90^circ)/(360^circ) xx  square xx 7^2 -  square xx 7^2]`

= `2[1/4 xx 154 -  square]`

= `2/2[77 -  square]`

= `square` cm2

Fill in the Blanks
Sum
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Solution

Area of shaded region = 2(Area of sector BAD − Area of ΔABD)

= \[\left[\frac{90°}{360°} \times \boxed{\frac{22}{7}} \times 7^2 - \boxed{\frac{1}{2}} \times 7^2\right]\]

= \[2\left[\frac{1}{4} \times 154 - \boxed{\frac{49}{2}}\right]\]

= \[\frac{2}{2}\left[77 - \boxed{49}\right]\]

= \[\boxed{28}\] cm2

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Chapter 7: Mensuration - Q.3 (A)
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