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SSC (English Medium) 10th Standard - Maharashtra State Board Question Bank Solutions for Geometry Mathematics 2

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Geometry Mathematics 2
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Draw an equilateral ΔABC with side 6.2 cm and construct its circumcircle

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

In the following figure seg AB ⊥ seg BC, seg DC ⊥ seg BC. If AB = 2 and DC = 3, find `(A(triangleABC))/(A(triangleDCB))`

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

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The ratio of the areas of two triangles with the common base is 14 : 9. Height of the larger triangle is 7 cm, then find the corresponding height of the smaller triangle.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

In the following figure RP : PK= 3 : 2, then find the value of A(ΔTRP) : A(ΔTPK).

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Find the distance between the following pairs of points:

(2, 3), (4, 1)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Find the distance between the following pairs of points:

(−5, 7), (−1, 3)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Find the length of the altitude of an equilateral triangle with side 6 cm.

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

The ratio of the areas of two triangles with common base is 6:5. Height of the larger triangle of 9 cm, then find the corresponding height of the smaller triangle.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

In the given figure, AD is the bisector of the exterior ∠A of ∆ABC. Seg AD intersects the side BC produced in D. Prove that:

\[\frac{BD}{CD} = \frac{AB}{AC}\]
[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

In the given figure, BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find `("A"(∆"ABC"))/("A"(∆"ADB"))`

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

In adjoining figure, PQ ⊥ BC, AD ⊥ BC then find following ratios.

  1. `("A"(∆"PQB"))/("A"(∆"PBC"))`
  2. `("A"(∆"PBC"))/("A"(∆"ABC"))`
  3. `("A"(∆"ABC"))/("A"(∆"ADC"))`
  4. `("A"(∆"ADC"))/("A"(∆"PQC"))`
[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

 In trapezium PQRS, side PQ || side SR, AR = 5AP, AS = 5AQ then prove that, SR = 5PQ 

 

 

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

In trapezium ABCD, side AB || side DC, diagonals AC and BD intersect in point O. If AB = 20, DC = 6, OB = 15 then Find OD. 

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

∆ABC ~ ∆LMN. In ∆ABC, AB = 5.5 cm, BC = 6 cm, CA = 4.5 cm. Construct ∆ABC and ∆LMN such that `"BC"/"MN" = 5/4`.

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

∆RST ~ ∆XYZ. In ∆RST, RS = 4.5 cm, ∠RST = 40°, ST = 5.7 cm Construct ∆RST and ∆XYZ, such that \[\frac{RS}{XY} = \frac{3}{5} .\]

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

Find the distance between the following pair of point.

 P(–5, 7), Q(–1, 3)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Find the distance between the following pair of points.

R(0, -3), S(0, `5/2`)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Find the distance between the following pair of points.

L(5, –8), M(–7, –3)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Find the distance between the following pair of point.

T(–3, 6), R(9, –10)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined
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