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Maharashtra State BoardSSC (English Medium) 10th Standard

Find the distance between the following pair of point. T(–3, 6), R(9, –10)

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Question

Find the distance between the following pair of point.

T(–3, 6), R(9, –10)

Numerical
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Solution

T(–3, 6), R(9, –10)

Let T (x1, y1) and R (x2, y2) be the given points.
∴ x1 = −3, y1 = 6, x2 = 9, y2 = −10

\[\mathrm{d(T,R)}=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}\]

= \[\sqrt{\left[9-(-3)\right]^{2}+\left(-10-6\right)^{2}}\]

= \[\sqrt{\left(9+3\right)^{2}+\left(-10-6\right)^{2}}\]

= \[\sqrt{12^{2}+\left(-16\right)^{2}}\]

= \[\sqrt{144 + 256}\]

= \[\sqrt{400}\]

= 20

∴ d(T, R) = 20 units

∴ The distance between the points T and R 20 units.

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Chapter 5: Co-ordinate Geometry - Practice Set 5.1 [Page 107]

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Balbharati Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
Chapter 5 Co-ordinate Geometry
Practice Set 5.1 | Q 1.5 | Page 107

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