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(English Medium) ICSE Class 9 - CISCE Question Bank Solutions

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Factorise the following by grouping the terms:

`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`

[5] Factorisation
Chapter: [5] Factorisation
Concept: undefined >> undefined

Factorise the following by grouping the terms:
2p(a2 - 2b2) -14p + (a2 - 2b2)2 - 7(a2 - 2b2)

[5] Factorisation
Chapter: [5] Factorisation
Concept: undefined >> undefined

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Evaluate the following:

`(2^3 xx 3^5 xx 24^2)/(12^2 xx 18^3 xx 27)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate the following:

`(4^3 xx 3^7 xx 5^6)/(5^8 xx 2^7 xx 3^3)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate the following:

`(12^2 xx 75^-2 xx 35 xx 400)/(48^2 xx 15^-3 xx 525)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate the following:

`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate the following:

`(1 - 15/64)^(-1/2)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate the following:

`(8/27)^((-2)/3) - (1/3)^-2 - 7^0`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate the following:

`9^(5/2) - 3 xx 5^0 - (1/81)^((-1)/2)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate the following:

`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate the following:

`16^(3/4) + 2(1/2)^-1 xx 3^0`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate the following:

`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x:
22x+1= 8

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x:
`9 xx 3^x = (27)^(2x - 5)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x:
3 x 7x = 7 x 3x

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x:
2x + 3 + 2x + 1 = 320

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x:
22x+3 - 9 x 2x + 1 = 0

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x:
1 = px

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x:
p3 x p-2 = px

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x:

`"p"^-5 = (1)/"p"^(x + 1)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined
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