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Science (English Medium) Class 12 - CBSE Question Bank Solutions for Mathematics

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If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = sin t, y = cos 2t

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = 4t, y = `4/y`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

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If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = cos θ – cos 2θ, y = sin θ – sin 2θ

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a (θ – sin θ), y = a (1 + cos θ)

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

`x = (sin^3t)/sqrt(cos 2t), y = (cos^3t)/sqrt(cos 2t)`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = `a(cos t + log tan  t/2)`, y = a sin t

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a sec θ, y = b tan θ

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a (cos θ + θ sin θ), y = a (sin θ – θ cos θ)

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x = `sqrt(a^(sin^(-1)t))`, y = `sqrt(a^(cos^(-1)t))` show that `dy/dx = - y/x`.

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If A is a 3 × 3 invertible matrix, then what will be the value of k if det(A–1) = (det A)k

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

if `A = ((2,3,1),(1,2,2),(-3,1,-1))`, Find `A^(-1)` and hence solve the system of equations 2x + y – 3z = 13, 3x + 2y + z = 4, x + 2y – z = 8

[3] Matrices
Chapter: [3] Matrices
Concept: undefined >> undefined

If x = a (2θ – sin 2θ) and y = a (1 – cos 2θ), find `dy/dx` when `theta = pi/3`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined
\[\int\limits_4^9 \frac{1}{\sqrt{x}} dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
\[\int\limits_{- 2}^3 \frac{1}{x + 7} dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
\[\int\limits_0^{1/2} \frac{1}{\sqrt{1 - x^2}} dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
\[\int\limits_0^1 \frac{1}{1 + x^2} dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
\[\int\limits_2^3 \frac{x}{x^2 + 1} dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
\[\int\limits_0^\infty \frac{1}{a^2 + b^2 x^2} dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
\[\int\limits_{- 1}^1 \frac{1}{1 + x^2} dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
\[\int\limits_0^\infty e^{- x} dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
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