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If `A = ((2,3,1),(1,2,2),(-3,1,-1))`, Find `A^(-1)` And Hence Solve the System of Equations 2x + Y – 3z = 13, 3x + 2y + Z = 4, X + 2y – Z = 8

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Question

if `A = ((2,3,1),(1,2,2),(-3,1,-1))`, Find `A^(-1)` and hence solve the system of equations 2x + y – 3z = 13, 3x + 2y + z = 4, x + 2y – z = 8

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Solution

We have `A = [(2,3,1),(1,2,2),(-3,1,-1)]`

`". |A| = [(2,3,1),(1,2,2),(-3,1,-1)]`

=2(−2 −2) − 3(−1 + 6) +1(1 + 6)

=−8 − 15 + 7=−16 ≠ 0

So, A is invertible.

Let Cij be the co-factors of the elements aij in A[aij]. Then,

Now, the given system of equations is expressible as

Hence, x = 1, = 2 and = −3 is the required solution.

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2016-2017 (March) Delhi Set 3

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