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Question
Write the structure of the major organic product in the following reaction:
\[\ce{C6H5ONa + C2H5Cl ->}\]
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Solution 1
\[\ce{\underset{sodium phenoxide}{C6H5O^-Na} + \underset{ethyl chloride}{C2H5Cl} ->[Williamson Synthesis] \underset{phenetole}{C6H5 - O - C2H5} + NaCl}\]
Solution 2

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The product formed in the first step of the reaction
\[\begin{array}{cc}
\ce{Br}\phantom{......}\\
|\phantom{.......}\\
\ce{CH3-CH2-CH-CH2-CH-CH3}\\
\phantom{...............}|\\
\phantom{................}\ce{Br}
\end{array}\]
with excess Mg/Et2O(Et = C2H5) is:
Explain why Grignard reagents should be prepared under anhydrous conditions.
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Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
