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प्रश्न
Write the structure of the major organic product in the following reaction:
\[\ce{C6H5ONa + C2H5Cl ->}\]
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उत्तर १
\[\ce{\underset{sodium phenoxide}{C6H5O^-Na} + \underset{ethyl chloride}{C2H5Cl} ->[Williamson Synthesis] \underset{phenetole}{C_6H_5 - O - C_2H_5} + NaCl}\]
उत्तर २
संबंधित प्रश्न
Explain why Grignard reagents should be prepared under anhydrous conditions?
What happens when methyl bromide is treated with sodium in the presence of dry ether?
Write the structure of main compounds A and B in the following reaction:
What would be the reactant and reagent used to obtain 2, 4-dimethyl pentan-3-ol?
Which of the following statements are correct about the reaction intermediate?
(i) Intermediate (c) is unstable because in this carbon is attached to 5 atoms.
(ii) Intermediate (c) is unstable because carbon atom is sp2 hybridised.
(iii) Intermediate (c) is stable because carbon atom is sp2 hybridised.
(iv) Intermediate (c) is less stable than the reactant (b).
\[\ce{R - CH2 - CCl2 - R ->[Peagent] R - C ≅ C - R}\]. The reagent is:-
A product (1) of above reaction is:-
The product formed in the first step of the reaction
\[\begin{array}{cc}
\ce{Br}\phantom{......}\\
|\phantom{.......}\\
\ce{CH3-CH2-CH-CH2-CH-CH3}\\
\phantom{...............}|\\
\phantom{................}\ce{Br}
\end{array}\]
with excess Mg/Et2O(Et = C2H5) is:
Explain why Grignard reagents should be prepared under anhydrous conditions.
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
