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प्रश्न
Write the structure of the major organic product in the following reaction:
\[\ce{C6H5ONa + C2H5Cl ->}\]
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उत्तर १
\[\ce{\underset{sodium phenoxide}{C6H5O^-Na} + \underset{ethyl chloride}{C2H5Cl} ->[Williamson Synthesis] \underset{phenetole}{C_6H_5 - O - C_2H_5} + NaCl}\]
उत्तर २
संबंधित प्रश्न
How will you bring about the following conversion?
1-Chlorobutane to n-octane
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(i) Intermediate (c) is unstable because in this carbon is attached to 5 atoms.
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(iv) Intermediate (c) is less stable than the reactant (b).
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\[\ce{R - CH2 - CCl2 - R ->[Peagent] R - C ≅ C - R}\]. The reagent is:-
The product formed in the first step of the reaction
\[\begin{array}{cc}
\ce{Br}\phantom{......}\\
|\phantom{.......}\\
\ce{CH3-CH2-CH-CH2-CH-CH3}\\
\phantom{...............}|\\
\phantom{................}\ce{Br}
\end{array}\]
with excess Mg/Et2O(Et = C2H5) is:
Explain why Grignard reagents should be prepared under anhydrous conditions.
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
Explain why Grignard reagents should be prepared under anhydrous conditions?
