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Question
Write a short note on the following.
Schotten-Baumann reaction
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Solution
Aniline reacts with benzoyl chloride (C6H5COCl) in the presence of NaOH to give N-phenyl benzamide. This reaction is known as the Schotten Baumann reaction. The acylation and benzoylation are nucleophilic substitutions.
\[\begin{array}{cc}
\phantom{..........}\ce{O}\phantom{..........................}\ce{O}\phantom{..}\\
\phantom{.........}||\phantom{..........................}||\phantom{.}\\
\ce{\underset{(Aniline)}{C6H5 - NH2} + \underset{(Benzoyl chloride)}{C6H5 - C - Cl} ->[NaOH] \underset{(N-phenyl benzamide)}{C6H5 - NH - C - C6H5} + HCl}
\end{array}\]
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RELATED QUESTIONS
In the following
The compound ‘B’ is _______.
(A) Propan–1–amine
(B) Propan–2–amine
(C) Isopropylamine
(D) Dimethylamine
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Reason: Bromine catalyses hydrolysis of acetamide.
The product formed by the reaction an aldehyde with a primary amine ____________.
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\[\begin{array}{cc}
\ce{O}\phantom{.........}\\
||\phantom{.........}\\
\ce{H - \underset{(A)}{C} - NH - CH3}
\end{array}\]
and
\[\begin{array}{cc}
\ce{O}\\
||\\
\ce{CH3 - \underset{(B)}{C} - NH2}
\end{array}\]
are which type of isomers?
Name the distinguishing test for differentiating 1° amine from 2° and 3° amine.
Define Amines.
Write a short note on the following.
Ammonolysis
