Question

Write a short note on the following.

Schotten-Baumann reaction

Answer 1

Aniline reacts with benzoyl chloride (C₆H₅COCl) in the presence of NaOH to give N-phenyl benzamide. This reaction is known as the Schotten Baumann reaction. The acylation and benzoylation are nucleophilic substitutions.

\[\begin{array}{cc}
\phantom{..........}\ce{O}\phantom{..........................}\ce{O}\phantom{..}\\
\phantom{.........}||\phantom{..........................}||\phantom{.}\\
\ce{\underset{(Aniline)}{C6H5 - NH2} + \underset{(Benzoyl chloride)}{C6H5 - C - Cl} ->[NaOH] \underset{(N-phenyl benzamide)}{C6H5 - NH - C - C6H5} + HCl}
\end{array}\]