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Questions
Account for the following.
Ethylamine is soluble in water whereas aniline is not.
State reasons for the following:
Ethylamine is soluble in water whereas aniline is insoluble in water.
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Solution 1
Ethylamine, when added to water, forms intermolecular H-bonds with water and therefore it is soluble in water. But aniline does not form an H-bond with water to a very large extent due to the presence of a large hydrophobic –C6H5 group. Hence, aniline is insoluble in water.

Solution 2
Ethylamine (C2H5NH2) exhibits solubility in water because the –NH group effectively forms hydrogen bonds with water molecules, due to the increased electron density on the nitrogen atom resulting from the +I inductive effect of the –C2H5 group. Also, the hydrocarbon part, –C2H5, is small and contributes much to hydrophobicity.
In Aniline (C6H5NH2), the –NH2 group is involved in resonance with the directly attached benzene ring, hence limiting its ability to form effective hydrogen bonds with water. Secondly, the benzene ring is substantial and generally hydrophobic. Hence, the net result is the insolubility of aniline in water.
RELATED QUESTIONS
Choose the most correct option.
Identify ‘B’ in the following reactions
\[\ce{CH3 - C ≡ N ->[Na/C2H5OH] A ->[NaNO2/dilHCl]B}\]
Which of the following amines does not undergo acetylation?
How will you prepare propan-1-amine from 1-nitropropane?
The following amine can be classified as (C2H5)2NH:
The following amine can be classified as:

Arrange the following in the increasing order of their basic strength:
C2H5NH2, C6H5NH2, (C2H5)2NH
\[\begin{array}{cc}
\ce{O}\phantom{.........}\\
||\phantom{.........}\\
\ce{H - \underset{(A)}{C} - NH - CH3}
\end{array}\]
and
\[\begin{array}{cc}
\ce{O}\\
||\\
\ce{CH3 - \underset{(B)}{C} - NH2}
\end{array}\]
are which type of isomers?
Among the following, which is the strongest base?
Write a short note on the following.
Ammonolysis
Write short note on Ammonolysis.
