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Question
Why does compound (A) given below not form an oxime?

(A)
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Solution
Glucose pentaacetate (structure A) does not have a free –OH group at C, and therefore, cannot be converted to the open chain form to give a free –CHO group and hence it does not form the oxime.

(Structure A)
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| (I) | ![]() |
| (II) | ![]() |
| (III) | ![]() |
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