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Question
Why can aryl halides not be prepared by reaction of phenol with \[\ce{HCl}\] in the presence of \[\ce{ZnCl2}\]?
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Solution
Aryl halides can't be prepared by reaction of phenol with \[\ce{HCl}\] in presence of \[\ce{ZnCl2}\] because the carbon-oxygen bond in phenols has partial double bond character and it, being stronger than a single bond, is difficult to break.
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RELATED QUESTIONS
Draw the structure of major monohalo products in the following reaction:

Draw the structure of major monohalo products in the following reaction:

In which of the following molecules carbon atom marked with asterisk (*) is asymmetric?
(a) \[\begin{array}{cc}
\ce{H}\\
|\\
\phantom{.}\ce{C^*}\phantom{}\\
\phantom{}/\phantom{..}|\phantom{..}\backslash\phantom{}\\
\phantom{.}\ce{I}\phantom{...}\ce{Br}\phantom{..}\ce{Cl}
\end{array}\]
(b) \[\begin{array}{cc}
\ce{D}\\
|\\
\phantom{.}\ce{C^*}\phantom{}\\
\phantom{}/\phantom{..}|\phantom{..}\backslash\phantom{}\\
\phantom{.}\ce{I}\phantom{...}\ce{Br}\phantom{..}\ce{Cl}
\end{array}\]
(c) \[\begin{array}{cc}
\ce{H}\\
|\\
\phantom{.}\ce{C^*}\phantom{}\\
\phantom{}/\phantom{..}|\phantom{..}\backslash\phantom{}\\
\phantom{..}\ce{OH}\phantom{..}\ce{C2H5}\phantom{}\ce{CH3}
\end{array}\]
(d) \[\begin{array}{cc}
\ce{H}\\
|\\
\phantom{.}\ce{C^*}\phantom{}\\
\phantom{}/\phantom{..}|\phantom{..}\backslash\phantom{}\\
\phantom{..}\ce{H}\phantom{...}\ce{C2H5}\phantom{}\ce{CH3}
\end{array}\]
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\[\begin{array}{cc}
\phantom{}\ce{HO}\phantom{.....}\ce{OH}\phantom{..}\ce{H}\phantom{.....}\ce{O}\phantom{..}\\
\phantom{..}\backslash\phantom{.....}|\phantom{....}|\phantom{.....}//\phantom{.}\\
\ce{\overset{a}{C} - \overset{b}{C} - \overset{c}{C} - \overset{d}{C}}\\
\phantom{..}//\phantom{.....}|\phantom{....}|\phantom{....}\phantom{.}\backslash\phantom{...}\\
\phantom{}\ce{O}\phantom{......}\ce{H}\phantom{...}\ce{OH}\phantom{...}\ce{H}\phantom{}\\
\end{array}\]
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CH3C(C2H5 )2CH2Br
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CH3CH2C(CH3)2CH2I
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\[\ce{CH3CH2C(CH3)2CH2I}\]
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IUPAC name of
is ______.
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is an example of ______.
