मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Why can aryl halides not be prepared by reaction of phenol with HCl in the presence of ZnClX2?

Advertisements
Advertisements

प्रश्न

Why can aryl halides not be prepared by reaction of phenol with \[\ce{HCl}\] in the presence of \[\ce{ZnCl2}\]?

टीपा लिहा
Advertisements

उत्तर

Aryl halides can't be prepared by reaction of phenol with \[\ce{HCl}\] in presence of \[\ce{ZnCl2}\] because the carbon-oxygen bond in phenols has partial double bond character and it, being stronger than a single bond, is difficult to break.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Haloalkanes and Haloarenes - Exercises [पृष्ठ १४४]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 10 Haloalkanes and Haloarenes
Exercises | Q III. 63. | पृष्ठ १४४

संबंधित प्रश्‍न

Draw the structures of major monohalo products in each of the following reaction:


Draw the structure of the major monohalo product in the following reaction:


Name the following halide according to the IUPAC system and classify it as an alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halide:

CH3CH2C(CH3)2CH2I


Name the following halide according to the IUPAC system and classify it as an alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halide:

(CH3)3CCH2CH(Br)C6H5


m-Xylene reacts with Br2 in presence of FeBr3, what are products formed:


Identify the compound Y in the following reaction.


Which of the following is an example of vic-dihalide?


Which of the products will be major product in the reaction given below? Explain.

\[\ce{CH3CH = CH2 + HI -> \underset{(A)}{CH3CH2CH2I} + \underset{(B)}{CH3CHICH3}}\]


Match the structures of compounds given in Column I with the classes of compounds given in Column II.

  Column I Column II
(i) \[\begin{array}{cc}
\ce{CH3 - CH - CH3}\\
|\phantom{..}\\
\ce{X}\phantom{..}
\end{array}\]
(a) Aryl halide
(ii) \[\ce{CH2 = CH - CH2 - X}\] (b) Alkyl halide
(iii) (c) Vinyl halide
(iv) \[\ce{CH2 = CH - X}\] (d) Allyl halide

Two isomers (A) and (B) with molar mass 184 g/mol and elemental composition C 52.2%; H 4.9% and Br 42.9% gave benzoic acid and p-bromobenzoic acid, respectively on oxidation with KMnO4. Isomer ‘A’ is optically active and gives a pale yellow precipitate when warmed with alcoholic AgNO3. Isomer ‘A’ and ‘B’ are, respectively:


Name the following halides according to the IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halides:

CH3C(C2H5 )2CH2Br


Name the following halide according to IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halide:

\[\ce{CH3C(C2H5)2CH2Br}\]


Name the following halide according to the IUPAC system and classify it as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halide:

\[\ce{CH_3CH_2C(CH_3)_2CH_2I}\]


Name the following halide according to the IUPAC system and classify it as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halide:

CH3CH2C(CH3)2CH2I


Name the following halide according to IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halides:

\[\ce{CH3C(Cl)(C2H5)CH2CH3}\]


Name the following halide according to IUPAC system and classify as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halide:

\[\ce{CH3C(Cl)(C2H5)CH2CH3}\]


Name the following halides according to IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halides:

\[\ce{CH3CH2C(CH3)2CH2I}\]


IUPAC name of \[\begin{array}{cc}
\phantom{}\ce{CH3}\phantom{..........}\ce{Br}\phantom{........}\\
\phantom{}|\phantom{................}|\phantom{.........}\\
\phantom{}\ce{CH3CHCH2CHCHCH2CH3}\phantom{}\\
\phantom{}|\phantom{..}\\
\phantom{..}\ce{CH3}\phantom{}
\end{array}\] is ______.


The IUPAC name of the compound shown below is:


Which of the following is an example of vicdihalide?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×