Advertisements
Advertisements
Question
What is the work done when the force on the object and the displacement of the object are perpendicular to each other?
Advertisements
Solution
The work done is zero because:
Work done = force x displacement x cos 0
Now, since 0 = 90°; cos 0 = and hence work done is equal to zero.
APPEARS IN
RELATED QUESTIONS
A body is moved in a direction opposite to the direction of force acting on it. State whether the work is done by the force or work is done against the force
Give an example when work done by the force of gravity acting on a body is zero even though the body gets displaced from its initial position.
What do you mean by equilibrium of a body?
Work is a scalar quantity because it is a measure of transfer of energy without indicating any direction
A man spends 7.4 kJ energy in displacing a body by 74 m in the direction in which he applies force, in 2.5 s. Calculate the power spent (in H.P) by the man.
How is 1 kgf related to the SI unit of force?
What do you understand by work? Is work a scalar or a vector quantity?
State the practical unit mainly used in mechanical engineering and write down its equivalent in watt.
For the following scenario, state whether the work done by gravity is positive, negative, or zero.
A car in neutral gear is coming down the slope.
A boy weighing 50 kgf climbs up from the first floor at a height of 3 m above the ground to the third floor at a height of 9 m above the ground. What will be the increase in his gravitational potential energy? (Take g = 10 N kg-1).
