Advertisements
Advertisements
प्रश्न
What is the work done when the force on the object and the displacement of the object are perpendicular to each other?
Advertisements
उत्तर
The work done is zero because:
Work done = force x displacement x cos 0
Now, since 0 = 90°; cos 0 = and hence work done is equal to zero.
APPEARS IN
संबंधित प्रश्न
When a body moves in a circular path, how much work is done by the body? Give reason.
(Hint: The body is acted upon by the centripetal force.)
The work done by a fielder when he takes a catch in a cricket match, is negative. Explain.
What do you mean by a centrifugal force?
State the condition when the work done by the force is positive
State the condition when the work done by the force is negative.
What is the S.I. unit of work? Define it.
A coolie carrying a load on his head and moving on a frictionless horizontal platform does no work. Explain the reason why.
A force of 1 kgf displaces a body by a distance of 10 cm
(i) in direction of force,
(ii) normal to the force
(iii) at an angle of 60° to the direction of the force.
Calculate the amount of work done in each case. (Take: g = 9.8 ms−2 )
A boy weighing 50 kgf climbs up from the first floor at a height of 3 m above the ground to the third floor at a height of 9 m above the ground. What will be the increase in his gravitational potential energy? (Take g = 10 N kg-1).
