Advertisements
Advertisements
प्रश्न
What is the work done when the force on the object and the displacement of the object are perpendicular to each other?
Advertisements
उत्तर
The work done is zero because:
Work done = force x displacement x cos 0
Now, since 0 = 90°; cos 0 = and hence work done is equal to zero.
APPEARS IN
संबंधित प्रश्न
If the power of a motor is 100 kW, at what speed can it raise a load of 50,000 N?
Draw a simplified diagram of a lemon crusher, indicting of load and effort
State two factors on which power spent by a source depends. Explain your answer with examples.
Name the quality which is measured in kWh.
A man spends 7.4 kJ energy in displacing a body by 74 m in the direction in which he applies force, in 2.5 s. Calculate the power spent (in H.P) by the man.
How is 1 kgf related to the SI unit of force?
What do you understand by work? Is work a scalar or a vector quantity?
Derive a relation between the S.I. and C.G.S. unit of force.
A force of 1 kgf displaces a body by a distance of 10 cm
(i) in direction of force,
(ii) normal to the force
(iii) at an angle of 60° to the direction of the force.
Calculate the amount of work done in each case. (Take: g = 9.8 ms−2 )
