Advertisements
Advertisements
प्रश्न
A man spends 7.4 kJ energy in displacing a body by 74 m in the direction in which he applies force, in 2.5 s. Calculate the power spent (in H.P) by the man.
Advertisements
उत्तर
Power spent = `"work done"/"time taken"`
P = `(7.4 xx 10^3)/2.5`
P = 2960 W
∴ 1 H.P = 746 W
∴ 1 W = `1/746` HP
∴ 2960 W = `2960/746`HP
∴ 2960 W = 3.97 HP
APPEARS IN
संबंधित प्रश्न
Draw a simplified diagram of a lemon crusher, indicting of load and effort
One horse power is equal to ______.
Name the quality which is measured in Wh.
What do you understand by the clockwise and anti clockwise moment of force?
What is the work done when the force on the object and the displacement of the object are perpendicular to each other?
It takes 20 s for a person A of mass 50 kg to climb up the stairs, while another person B of same mass does the same in 15 s. Compare the power developed by the persons A and B.
A bullet fired against a window glass pane makes a hole in it without any cracks while a stone striking the same glass pane smashes it; explain with reason.
State the practical unit mainly used in mechanical engineering and write down its equivalent in watt.
The world record for weight lifting was held by Sergei Didyk of the USSR. He lifted 261 kg to a height of 2.3 m in 4s; find:
(a) Weight lifted by him
(b) Work done by him
(c) Power developed by him. (g = 10m/s2)
