Advertisements
Advertisements
प्रश्न
A weight lifter lifted a load of 200 kgf to a height of 2.5 m in 5 s. Calculate:
- the work done, and
- the power developed by him. Take g = 10 N kg-1
Advertisements
उत्तर
Force= mg = 200 × 10 = 2000 N
Distance, S = 2.5m
Time , t = 5 s
(i) Work done, W= F × S
W = 2000 × 2.5m = 5000 J
(ii) Power developed = `w/t`= `5000/5` = 1000 W
APPEARS IN
संबंधित प्रश्न
How is work related to energy?
A water pump raises 50 litres of water through a height of 25 m in 5 s. Calculate the power of the pump required.
(Take g = 10 N kg-1 and density of water = 1000 kg m-3)
The work done on an object does not depend on ______.
Does the earth move around the sun with a uniform velocity?
________ is said to be done when a force is acting on it.
A is a push or a pull ______.
A body of mass 0.5 kg travels on straight line path with velocity v = (3x2 + 4) m/s. The net work done by the force during its displacement from x = 0 tox = 2 m is ______.
