Advertisements
Advertisements
Question
A man spends 7.4 kJ energy in displacing a body by 74 m in the direction in which he applies force, in 2.5 s. Calculate the power spent (in H.P) by the man.
Advertisements
Solution
Power spent = `"work done"/"time taken"`
P = `(7.4 xx 10^3)/2.5`
P = 2960 W
∴ 1 H.P = 746 W
∴ 1 W = `1/746` HP
∴ 2960 W = `2960/746`HP
∴ 2960 W = 3.97 HP
APPEARS IN
RELATED QUESTIONS
If the power of a motor is 100 kW, at what speed can it raise a load of 50,000 N?
Give the expression for mechanical advantage of an inclined plane in terms of the length of an inclined plane.
A body of mass m is moving with a uniform velocity u. A force is applied on the body due to which its velocity changes from u to v. How much work is being done by the force?
State the condition when a force produces
(i) linear motion.
(ii) rotational motion, in a body.
How is 1 kgf related to the SI unit of force?
A bullet fired against a window glass pane makes a hole in it without any cracks while a stone striking the same glass pane smashes it; explain with reason.
Derive a relation between the S.I. and C.G.S. unit of force.
State the C.G.S. unit of work. How it is related to its S.I. unit?
A force of 1 kgf displaces a body by a distance of 10 cm
(i) in direction of force,
(ii) normal to the force
(iii) at an angle of 60° to the direction of the force.
Calculate the amount of work done in each case. (Take: g = 9.8 ms−2 )
