Advertisements
Advertisements
Question
A man spends 7.4 KJ energy in displacing a body by 74 m in the direction in which he applies force in 2.5 s. Calculate the force applied.
Advertisements
Solution
Work done by man = 7.4 kJ
Distance moved, S = 74 m
Work done by the man= Force x distance moved in direction of force
Work, W = F × S
7.4 × 103 = F × 74
F = `(7.4 ×10^3)/74`
F = 100 N
APPEARS IN
RELATED QUESTIONS
A body is moved in a direction opposite to the direction of force acting on it. State whether the work is done by the force or work is done against the force
A body, when acted upon by a force of 10 kgf, gets displaced by 0.5 m. Calculate the work done by the force, when the displacement is (i) in the direction of force, (ii) at an angle of 60° with the force, and (iii) normal to the force. (g = 10 N kg-1)
Name the quality which is measured in kW.
What do you mean by equilibrium of a body?
An engine does 54,000 J of work by exerting a force of 6000 N on it. What is the displacement in the direction of the force?
State the condition when the work done by the force is negative.
Derive a relation between the S.I. and C.G.S. unit of force.
For the following scenario, state whether the work done by gravity is positive, negative, or zero.
A person climbs a ladder.
For the following scenario, state whether the work done by gravity is positive, negative, or zero.
A car in neutral gear is coming down the slope.
