Advertisements
Advertisements
प्रश्न
A man spends 7.4 kJ energy in displacing a body by 74 m in the direction in which he applies force, in 2.5 s. Calculate the power spent (in H.P) by the man.
Advertisements
उत्तर
Power spent = `"work done"/"time taken"`
P = `(7.4 xx 10^3)/2.5`
P = 2960 W
∴ 1 H.P = 746 W
∴ 1 W = `1/746` HP
∴ 2960 W = `2960/746`HP
∴ 2960 W = 3.97 HP
APPEARS IN
संबंधित प्रश्न
When a body moves in a circular path, how much work is done by the body? Give reason.
(Hint: The body is acted upon by the centripetal force.)
Give an example when work done by the force of gravity acting on a body is zero even though the body gets displaced from its initial position.
How is kilowatt hour related to joule?
Is it possible that no transfer of energy may take place even when a force is applied to a body?
What do you understand by the clockwise and anti clockwise moment of force?
What is the work done when the force on the object and the displacement of the object are perpendicular to each other?
State the condition when the work done by a force is negative. Explain with the help of examples.
A bullet fired against a window glass pane makes a hole in it without any cracks while a stone striking the same glass pane smashes it; explain with reason.
What is the S.I. unit of work? Define it.
