Advertisements
Advertisements
प्रश्न
A body is provided at a point. A force of 20 N is applied at a distance of 40 cm from the pivot. Find the moment of force about the pivot.
Advertisements
उत्तर
Given, applied force, F = 20N
Distance From the pivot , d = 40cm = 0.4m
Torque = F x d = 20 x 0.4 = 8 Nm
APPEARS IN
संबंधित प्रश्न
Name the quality which is measured in Wh.
State the factors on which moment of force about a point depends.
State the condition when a force produces
(i) linear motion.
(ii) rotational motion, in a body.
A mechanic can open a nut by applying a force of 200 N while using a lever handle of 50 cm length. How long handle is required if he wants to open it by applying a force of only 50 N?
Name the force needed for circular motion. What is the direction of the force?
An engine does 54,000 J of work by exerting a force of 6000 N on it. What is the displacement in the direction of the force?
Work done by a force is equal to the product of ....... and ....
A force F when acts on a body, displace it by a distance d in a direction at an angle θ with the direction of the force. Write down the expression for the work done by the force.
A coolie carrying a load on his head and moving on a frictionless horizontal platform does no work. Explain the reason why.
For the following scenario, state whether the work done by gravity is positive, negative, or zero.
A car in neutral gear is coming down the slope.
