Advertisements
Advertisements
प्रश्न
A body is provided at a point. A force of 20 N is applied at a distance of 40 cm from the pivot. Find the moment of force about the pivot.
Advertisements
उत्तर
Given, applied force, F = 20N
Distance From the pivot , d = 40cm = 0.4m
Torque = F x d = 20 x 0.4 = 8 Nm
APPEARS IN
संबंधित प्रश्न
When a body is placed on a table top, it exerts a force equal to its weight downwards on the table top but does not move or fall
1) Name the force exerted by the table top
2) What is the direction of the force?
State two factors on which power spent by a source depends. Explain your answer with examples.
What do you understand by the clockwise and anti clockwise moment of force?
State the principle of moments.
A mechanic can open a nut by applying a force of 200 N while using a lever handle of 50 cm length. How long handle is required if he wants to open it by applying a force of only 50 N?
A boy takes 3 minutes to lift a 20 litre water bucket from a 20 m deep well, while his father does it in 2 minutes. Compare:
- the work, and
- power developed by them.
What do you understand by work? Is work a scalar or a vector quantity?
State the condition when the work done by the force is negative.
Calculate the work done when:
A car is moved on a rough road through 30 m against a frictional resistance of 75 N.
A coolie carries a load of 30 kgf through a distance of 500 m in 5 minutes while another coolie B carries the same load through the same distance in 10 minutes. Compare the
(i) work done, and
(ii) power developed. (Take: g = 10md−2)
