Advertisements
Advertisements
प्रश्न
A mechanic can open a nut by applying a force of 200 N while using a lever handle of 50 cm length. How long handle is required if he wants to open it by applying a force of only 50 N?
Advertisements
उत्तर
Given force applied by a mechanic, F = 200 N
length of ever, d = 50 cm = 0.5m
Torque, τ F x d = 200 x 0.5 = 100Nm
Now, if the mechanic applies a force, F' = 50N
let d'be the length of the lever to produce the same torque.
the, τ = F' x d'
⇒ d' = `100/50` = 2 m
APPEARS IN
संबंधित प्रश्न
When a body is placed on a table top, it exerts a force equal to its weight downwards on the table top but does not move or fall
1) Name the force exerted by the table top
2) What is the direction of the force?
Name the quality which is measured in kWh.
A body of mass m is moving with a uniform velocity u. A force is applied on the body due to which its velocity changes from u to v. How much work is being done by the force?
How much force is applied on a body when 150 J of work is done in displacing the body through a distance of 10 m in the direction of the force?
State the condition when the work done by a force is negative. Explain with the help of examples.
A boy takes 3 minutes to lift a 20 litre water bucket from a 20 m deep well, while his father does it in 2 minutes.
How much work each does? Take density of water = 103 kg m-3 and g = 9.8 N kg-1.
State the condition when the work done by the force is negative.
Derive a relation between the S.I. and C.G.S. unit of force.
A machine raises a load of 750 N through a height of 16 m in 5 seconds. Calculate the power at which the machine works.
