Question

A mechanic can open a nut by applying a force of 200 N while using a lever handle of 50 cm length. How long handle is required if he wants to open it by applying a force of only 50 N?

Answer 1

Given force applied by a mechanic, F = 200 N

length of ever, d = 50 cm = 0.5m

Torque, τ F x d = 200 x 0.5 = 100Nm

Now, if the mechanic applies a force, F' = 50N

let d'be the length of the lever to produce the same torque.

the, τ = F' x d'

⇒ d' = `100/50` = 2 m