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प्रश्न
State two factors on which power spent by a source depends. Explain your answer with examples.
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उत्तर
A source's use of power depends on two things:
- The amount of work done by the source, and
- The time taken by the source to do the said work.
Example: Should a coolie A take one minute to raise a load to a bus roof, and another coolie B take two minutes to do the same, Both coolies accomplish the same amount of work; however, because coolie A works more quickly, the power expended by him is double that of coolie B.
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संबंधित प्रश्न
A stone of mass m is rotated in a circular path with a uniform speed by tying a strong string with the help of your hand. Answer the following questions
1) Is the stone moving with a uniform or variable speed?
2) Is the stone moving with a uniform acceleration? In which direction does the acceleration act?
3) What kind of force acts on the hand and state its direction?
Give an example when work done by the force of gravity acting on a body is zero even though the body gets displaced from its initial position.
Name the quality which is measured in kWh.
What do you mean by uniform circular motion?
What is the work done when the force on the object and the displacement of the object are perpendicular to each other?
Work is a scalar quantity because it is a measure of transfer of energy without indicating any direction
How much force is applied on a body when 150 J of work is done in displacing the body through a distance of 10 m in the direction of the force?
A coolie carrying a load on his head and moving on a frictionless horizontal platform does no work. Explain the reason why.
A coolie carries a load of 30 kgf through a distance of 500 m in 5 minutes while another coolie B carries the same load through the same distance in 10 minutes. Compare the
(i) work done, and
(ii) power developed. (Take: g = 10md−2)
A force of 1 kgf displaces a body by a distance of 10 cm
(i) in direction of force,
(ii) normal to the force
(iii) at an angle of 60° to the direction of the force.
Calculate the amount of work done in each case. (Take: g = 9.8 ms−2 )
