Advertisements
Advertisements
Question
What must be added to 2a3 + 5a – a2 – 6 to get a2 – a – a3 + 1?
Sum
Advertisements
Solution
We get, the required result by subtracting
2a3 + 5a – a2 – 6 from - a3 + a2 - a + 1
= (- a3 + a2 - a + 1) - (2a3 – a2 + 5a – 6)
= - a3 + a2 - a + 1 - 2a3 + a2 - 5a + 6
= - a3 - 2a3 + a2 + a2 - a - 5a + 1 + 6
= - 3a3 + 2a2 - 6a + 7
shaalaa.com
Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Subtract the sum of 3a2 – 2a + 5 and a2 – 5a – 7 from the sum of 5a2 -9a + 3 and 2a – a2 – 1
If m = 9x2 - 4xy + 5y2 and n = - 3x2 + 2xy - y2 find: 2m - n
Multiply: 3x, 5x2y and 2y
Evaluate: (5m - 2n)(5m + 2n)(25m2 + 4n2)
Simplify: `"x"/2+"x"/4`
Simplify: `"2p"/3 -"3p"/5`
Simplify: `"k"/2 + "k"/3 + "2k"/5`
Simplify: `"x" + "x"/2 + "x"/3`
Simplify: `"3y"/5 - "y + 2"/2`
Simplify: `("p" + "p"/3)("2p" + "p"/2)("3p" - "2p"/3)`
