By How Much Does 8x3 – 6x2 + 9x – 10 Exceed 4x3 + 2x2 + 7x -3 ? - Mathematics

By how much does 8x³ – 6x² + 9x – 10 exceed 4x³ + 2x² + 7x -3?

Sum

8x³ – 6x² + 9x – 10 exceeds 4x³ + 2x² + 7x -3

= (8x³ - 6x² + 9x - 10) - (4x³ + 2x² + 7x - 3)

= 8x³ - 6x² + 9x - 10 - 4x³ + 2x² + 7x - 3

= 8x³- 4x³ - 6x² - 2x² + 9x - 7x - 10 + 3

= 4x³ - 8x² + 2x - 7

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Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.

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Chapter 11: Fundamental Concepts (Including Fundamental Operations) - Exercise 11 (B)

Chapter 11 Fundamental Concepts (Including Fundamental Operations)
Exercise 11 (B) | Q 12