Advertisements
Advertisements
Question
Subtract: a2 - 3ab - 6b2 from 2b2 - a2 + 2ab
Advertisements
Solution
a2 - 3ab - 6b2 from 2b2 - a2 + 2ab
= (2b2 - a2 + 2ab) - (a2 - 3ab - 6b2)
= 2b2 - a2 + 2ab - a2 + 3ab + 6b2
= - a2 + a2 + 2b2 + 6b2 + 2ab + 3ab
= - 2a2 + 8b2 + 5ab
= 8b2 + 5ab - 2a2
APPEARS IN
RELATED QUESTIONS
The perimeter of a rectangle is 28x3+ 16x2 + 8x + 4. One of its sides is 8x2 + 4x. Find the other side
The perimeter of a triangle is 14a2 + 20a + 13. Two of its sides are 3a2 + 5a + 1 and a2 + 10a – 6. Find its third side.
Multiply: 5, 3a and 2ab2
Multiply: - 3m2n + 5mn - 4mn2 and 6m2n
Copy and complete the following multi-plication:
2a - b + 3c
× 2a - 4b
Copy and complete the following multiplication:
4x3 − 10x2 + 6x − 8
× 3 + 2x − x2
Multiply: 2mnpq, 4mnpq and 5 mnpq
Simplify: `"x"/2+"x"/4`
Simplify: `"k"/2 + "k"/3 + "2k"/5`
Simplify: `"x" + "x"/2 + "x"/3`
