If X = 4a2 + B2 - 6ab; Y = 3b2 - 2a2 + 8ab and Z = 6a2 + 8b2 - 6ab Find: X - Y - Z

If x = 4a² + b² - 6ab; y = 3b² - 2a² + 8ab and z = 6a² + 8b² - 6ab find: x - y - z

Sum

x = 4a² + b² - 6ab
y = 3b² - 2a² + 8ab
z = 6a² + 8b² - 6ab

x - y - z

= (4a² + b² - 6ab) - (3b² - 2a² + 8ab) - (6a² + 8b² - 6ab)

= 4a² + b² - 6ab - 3b² + 2a² - 8ab - 6a² - 8b² + 6ab

= 4a² - 2a² - 6a² + b² - 3b² - 8b² - 6ab - 8ab + 6ab

= 6a² - 6a² + b² - 11b² - 14ab + 6ab

= - 10b² - 8ab

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Chapter 13: Fundamental Concepts (Including Fundamental Operations) - Exercise 11 (B)

Chapter 13 Fundamental Concepts (Including Fundamental Operations)
Exercise 11 (B) | Q 20.2