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If X = 4a2 + B2 - 6ab; Y = 3b2 - 2a2 + 8ab and Z = 6a2 + 8b2 - 6ab Find: X - Y - Z

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Question

If x = 4a2 + b2 - 6ab; y = 3b2 - 2a2 + 8ab and z = 6a2 + 8b2 - 6ab find: x - y - z

Sum
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Solution

x = 4a2 + b2 - 6ab
y = 3b2 - 2a2 + 8ab
z = 6a2 + 8b2 - 6ab

x - y - z

= (4a2 + b2 - 6ab) - (3b2 - 2a2 + 8ab) - (6a2 + 8b2 - 6ab)

= 4a2 + b2 - 6ab - 3b2 + 2a2 - 8ab - 6a2 - 8b2 + 6ab

= 4a2 - 2a2 - 6a2 + b2 - 3b2 - 8b2 - 6ab - 8ab + 6ab 

= 6a2 - 6a2 + b2 - 11b2 - 14ab + 6ab

= - 10b2 - 8ab 

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Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.
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Q 20.2
Chapter 11: Fundamental Concepts (Including Fundamental Operations) - Exercise 11 (B)

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Selina Concise Mathematics [English] Class 7 ICSE
Chapter 11 Fundamental Concepts (Including Fundamental Operations)
Exercise 11 (B) | Q 20.2

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