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Question
If x = 4a2 + b2 - 6ab; y = 3b2 - 2a2 + 8ab and z = 6a2 + 8b2 - 6ab find: x + y + z
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Solution
x = 4a2 + b2 - 6ab
y = 3b2 - 2a2 + 8ab
z = 6a2 + 8b2 - 6ab
x + y + z
= 4a2 + b2 - 6ab + 3b2 - 2a2 + 8ab + 6a2 + 8b2 - 6ab
= 4a2 - 2a2 + 6a2 + b2 + 3b2 + 8b2 - 6ab + 8ab - 6ab
= 10a2 - 2a2 + 12b2 - 12ab + 8ab
= 8a2 + 12b2 - 4ab
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