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If X = 4a2 + B2 - 6ab; Y = 3b2 - 2a2 + 8ab and Z = 6a2 + 8b2 - 6ab Find: X + Y + Z

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Question

If x = 4a2 + b2 - 6ab; y = 3b2 - 2a2 + 8ab and z = 6a2 + 8b2 - 6ab find: x + y + z

Sum
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Solution

x = 4a2 + b2 - 6ab
y = 3b2 - 2a2 + 8ab
z = 6a2 + 8b2 - 6ab

x + y + z

= 4a2 + b2 - 6ab + 3b2 - 2a2 + 8ab + 6a2 + 8b2 - 6ab

= 4a2 - 2a2 + 6a2 + b2 + 3b2 + 8b2 - 6ab + 8ab - 6ab 

= 10a2 - 2a2 + 12b2 - 12ab + 8ab 

= 8a2 + 12b2 - 4ab 

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Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.
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Q 20.1
Chapter 13: Fundamental Concepts (Including Fundamental Operations) - Exercise 11 (B)

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R.K. Bansal Concise Mathematics [English] Class 7 ICSE
Chapter 13 Fundamental Concepts (Including Fundamental Operations)
Exercise 11 (B) | Q 20.1

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