Advertisements
Advertisements
Question
If x = 4a2 + b2 - 6ab; y = 3b2 - 2a2 + 8ab and z = 6a2 + 8b2 - 6ab find: x + y + z
Advertisements
Solution
x = 4a2 + b2 - 6ab
y = 3b2 - 2a2 + 8ab
z = 6a2 + 8b2 - 6ab
x + y + z
= 4a2 + b2 - 6ab + 3b2 - 2a2 + 8ab + 6a2 + 8b2 - 6ab
= 4a2 - 2a2 + 6a2 + b2 + 3b2 + 8b2 - 6ab + 8ab - 6ab
= 10a2 - 2a2 + 12b2 - 12ab + 8ab
= 8a2 + 12b2 - 4ab
APPEARS IN
RELATED QUESTIONS
Subtract: - 5a - 2b from b + 6c
Subtract – 5a2 – 3a + 1 from the sum of 4a2 + 3 – 8a and 9a – 7.
Multiply: 9xy + 2y2 and 2x - 3y
Copy and complete the following multi-plication:
9x + 5y
× - 3xy
Copy and complete the following multi-plication:
3xy - 2x2 - 6x
× -5x2y
Copy and complete the following multi-plication:
6 - 3x + 2x2
× 1 + 5x - x2
Simplify: `"3y"/4 -"y"/5`
Simplify: `"y"/5 + "y" - "19y"/15`
Simplify: `(5 ("x" - 4))/3 + (2(5x - 3))/5 + (6(x - 4))/7`
Simplify: `("5k"/8 - "3k"/5) div "k"/4`
