The Perimeter of a Triangle is 14a2 + 20a + 13. Two of Its Sides Are 3a2 + 5a + 1 and A2 + 10a – 6. Find Its Third Side.

The perimeter of a triangle is 14a² + 20a + 13. Two of its sides are 3a² + 5a + 1 and a² + 10a – 6. Find its third side.

Sum

perimeter of a triangle = 14a² + 20a + 13

Sum of two sides

= 3a² + 5a + 1 + a² + 10a - 6

= 3a² + a² + 5a + 10a + 1 - 6

= 4a² + 15a - 5

∴ Third side = (14a² + 20a + 13) - (4a² + 15a - 5)

= 14a² + 20a + 13 - 4a² - 15a + 5

= 14a² - 4a² + 20a - 15a + 13 + 5

= 10a² + 5a + 18

shaalaa.com

Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.

Is there an error in this question or solution?

Chapter 11: Fundamental Concepts (Including Fundamental Operations) - Exercise 11 (B)

Chapter 11 Fundamental Concepts (Including Fundamental Operations)
Exercise 11 (B) | Q 19