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प्रश्न
The perimeter of a triangle is 14a2 + 20a + 13. Two of its sides are 3a2 + 5a + 1 and a2 + 10a – 6. Find its third side.
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उत्तर
perimeter of a triangle = 14a2 + 20a + 13
Sum of two sides
= 3a2 + 5a + 1 + a2 + 10a - 6
= 3a2 + a2 + 5a + 10a + 1 - 6
= 4a2 + 15a - 5
∴ Third side = (14a2 + 20a + 13) - (4a2 + 15a - 5)
= 14a2 + 20a + 13 - 4a2 - 15a + 5
= 14a2 - 4a2 + 20a - 15a + 13 + 5
= 10a2 + 5a + 18
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