Advertisements
Advertisements
प्रश्न
What must be subtracted from a2 + b2 + lab to get – 4ab + 2b2?
बेरीज
Advertisements
उत्तर
We get, the required result by subtracting
– 4ab + 2b2 from a2 + b2 + 2ab
= a2 + b2 + 2ab – (– 4ab + 2b2)
= a2 + b2 + 2ab + 4ab – 2b2
= a2 + b2 – 2b2 + 2ab + 4ab
= a2 – b2 + 6ab
shaalaa.com
Performs Operations (Addition and Subtraction) on Algebraic Expressions with Integral Coefficients Only.
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Subtract: - 5a - 2b from b + 6c
Subtract – 5a2 – 3a + 1 from the sum of 4a2 + 3 – 8a and 9a – 7.
Simplify: - 2m + 5 + 4(m - 3)
Multiply: 4a + 5b and 4a - 5b
Multiply: 6xy2 - 7x2y2 + 10x3 and - 3x2y3
Copy and complete the following multi-plication:
6 - 3x + 2x2
× 1 + 5x - x2
Evaluate: (3x - 2y)(4x + 3y)
Simplify: `"a"/10+"2a"/5`
Simplify: `"3y"/4 -"y"/5`
Simplify: `"6k"/7 - ("8k"/9 - "k"/3)`
